Question

A rectangle has twice the area of a square.The length of the rectangle is 12 cm greater and thr width is 8 cm greater than side a side of the square. Find the side of the square​

Answer 1

Let the side of square = x

Are of square = x^२

Rectangle length = (x+12)

rectangle width = (x+8)

Area of rectangle = (x+12)(x+8)

(x+12)(x+8) =2x^2

x^2+20x+96=2x^2

x^2-20x-96=0

x^2-24x+4x-96=0

x(x-24)+4(x-24)=0

(x-24)(x+4)=0

ignore negative

x= 24 the side of square

Perimeter of square = 24 *4 = 96cm