Question

A rectangle has twice the area of the square, the length of the rectangle is 12 cm greater and width is 8cm
greater than a side of the square, find the perimeter of the square?

Answer 1

Answer:

96 CM    (mark as brainliest please)

Step-by-step explanation:

side of square = x

Are of square = x^2

Rectangle length = (x+12)

rectangle width = (x+8)

Area of rectangle = (x+12)(x+8)

(x+12)(x+8) =2x²

x²+20x+96=2x²

x²-20x-96=0

x²-24x+4x-96=0

x(x-24)+4(x-24)=0

(x-24)(x+4)=0

ignore negative sign

x= 24 the side of square

Perimeter of square = 24 *4 = 96cm