Question

A rectangle is 10 cm long and 8cm wide. work out the length of the diagonal of the rectangle ​

Answer 1

Answer:

12.80cm

Step-by-step explanation:

we can find the diagonal of the rectangle by phythagoras theorem

AC^2=AB^2+BC^2

a is 10cm

b is 8cm

diagonal=10^2+8^2

             =100+64

            =164

diagonal=square root of 164

              =12.80cm

Answer 2

Answer:

Question :

A rectangle is 10 cm long and 8cm wide. work out the length of the diagonal of the rectangle .

Answer :

We know that the diagonals divide the triangle into two right angled triangles.

Let AB be x and AC be 12 cm and BC be 8 cm.

Let AB be the diagonal.

So,

By using Pythagoras theorem, we can find the diagonal which is the hypotenuse of the right angled triangle.

Pythagoras theorem :

${AB}^{2} = {AB}^{2} + {BC}^{2} \\ \\ {AB}^{2} = {10}^{2} + {8}^{2} \\ \\ {AB}^{2} = 100 + 64 \\ \\ {AB}^{2} = 164 \\ \\ AB \: = \sqrt{164} \\ \\ AB = 12.80 \: cm$

Therefore

By using Pythagoras theorem, we found the hypotenuse of the triangle which is the diagonal of the rectangle.