Question

a rectangle is 12cm long and 5cm wide. ibrahim shades 7/10 of the rectangle. what area of the rectangle does ibrahim shade

Answer 1

$\bf \huge ☯A \blue n \green s \orange w \pink er$

$\star { \boxed { \rm{Area \: of \: rectangle = length \times breadth}}}$

${ \sf {:: \implies {{Area \: of \: rectangle = length \times breadth}}}}$

$\sf {:: \implies {{Area \: of \: rectangle = 12cm \times 5cm}}}$

$\sf {:: \implies {{Area \: of \: rectangle = 60 {cm}^{2} }}}$

$\sf{ : : \implies{Area \: shades \: by \: Imbrahim=Area \: of \: rectangle \times \frac{7}{10} }}$

$\sf{ : : \implies{Area \: shades \: by \: Imbrahim=60 {cm}^{2} \times \frac{7}{10} }}$

$\sf{ : : \implies{Area \: shades \: by \: Imbrahim= \cancel {60} {cm}^{2} \times \frac{7} {\cancel{10}} }}$

$\sf{ : : \implies{Area \: shades \: by \: Imbrahim= (7 \times 6) {cm}^{2} }}$

$\sf{ : : \implies{Area \: shades \: by \: Imbrahim= 42{cm}^{2} }}$

$\bf{Hence, }\: \: \: \: \: \: \: \: \: \: \: \: \: {\underline{ \boxed{ \rm{Area \: shades \: by \: Imbrahim= 42{cm}^{2} }}}}$

Answer 2

$\huge\pink{\boxed{\green {\mathbb{\overbrace {\underbrace{\fcolorbox{red}{aqua}{\underline{\pink{†◖ \: ⚆SOLTUON⚆◗†}}}}}}}}}$

$\star { \boxed { \tt{Area \: of \: rectangle = length \times breadth}}}⋆$

${ \tt {:: \implies {{Area \: of \: rectangle = length \times breadth}}}}$

$\tt{:: \implies {{Area \: of \: rectangle = 12cm \times 5cm}}}::⟹Areao$

$\tt{:: \implies {{Area \: of \: rectangle = 60 {cm}^{2} }}}$

$\tt{ : : \implies{Area \: shades \: by \: Imbrahim=Area \: of \: rectangle \times \frac{7}{10} }}::$

$\tt{ : : \implies{Area \: shades \: by \: Imbrahim=60 {cm}^{2} \times \frac{7}{10} }}$

$\tt{ : : \implies{Area \: shades \: by \: Imbrahim= \cancel {60} {cm}^{2} \times \frac{7} {\cancel{10}} }}::$

$\tt{ : : \implies{Area \: shades \: by \: Imbrahim= (7 \times 6) {cm}^{2} }}::$

$\tt{ : : \implies{Area \: shades \: by \: Imbrahim= 42{cm}^{2} }}$

$\mathbb{Hence, }\: \: \: \: \: \: \: \: \: \: \: \: \: {\underline{ \boxed{ \tt{Area \: shades \: by \: Imbrahim= 42{cm}^{2} }}}}$