Question

A rectangle is 16 CM by 9 CM. find a side of the square whose area equals the area of the rectangle .by how much does the perimeter of the rectangle exceed the perimeter of the square

Answer 1

length x breadth= area of rectangle= area of square
side ^2= 16 x 9
side of square= 12
perimeter of rectangle= 2(16+9)=50
perimeter of square 4 side=48
diff. in perimeter= 2
plz mark it as brianliest answer

Answer 2

Area of rectangle = (16 × 9) m2 = 144 m2

Given condition,

Area of square = Area of rectangle

∴ (Side)2 = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m