Question

A rectangle is 16 m by 9 m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed of the square?​

Answer 1

Answer:

The side of square is 12m

And perimeter of rect is greater than perimeter of square

by 2 m.

rest given in the explanation.

Step-by-step explanation:

Area of the rectangle = 16×9= 144m^2

Square root of 144 = 12

so the side of square is 12

now we will find the perimeter of rect and square

p of rect = 2(l+b) = 2(16+9) = 2(25) = 50m

now p of square = 4a= 4×12 = 48m

Therefore difference = 50 m - 48m = 2m