Question

A rectangle is 16 m by 9 m. Find a side of the squarewhose are equal the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square

Answer 1

Area is 16*9=144
Perimeter is 16*2+9*2=50 cm

Side of the square is squareroot of 144 = 12
Perimeter of square is 12*4=48

Rectangle exceeds by 2 .  (50-48)

Answer 2

Area of rectangle = (16 × 9) m2 = 144 m2

Given condition,

Area of square = Area of rectangle

∴ (Side)2 = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m