a rectangle is 16 m by 9 M find the side of the square whose area equals the area of the rectangle by how much does the perimeter of the rectangle exceeds the perimeter of the square
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area of rectangle = l*b
= 16* 9
= 144m^2
area of rectangle= area of square=144m^2
area of square=side2
144=side2
12m= side
perimeter of square = 4×(side
= 4×12
= 48m
perimeter of rectangle= 2(l+b)
= 2(16+9)
= 2(25)
= 50m
.: the perimeter of rectangle is more than the perimeter of square by 2m.
= 16* 9
= 144m^2
area of rectangle= area of square=144m^2
area of square=side2
144=side2
12m= side
perimeter of square = 4×(side
= 4×12
= 48m
perimeter of rectangle= 2(l+b)
= 2(16+9)
= 2(25)
= 50m
.: the perimeter of rectangle is more than the perimeter of square by 2m.
hariharan14:
By the way it is a math one u said its eng
i I am know English looked English so it automatically change to English I am so sorry Hariharan 14
I clicked English unknowingly so it automatically change to English so but it's actually and Math questions and by the way thanks
K how many stars will u give fr my ans
hi
Answered by
9
Area of rectangle = (16 × 9) m2 = 144 m2
Given condition,
Area of square = Area of rectangle
∴ (Side)2 = 144
Side = √144 = 12 m
Now,
Perimeter of square = 4 × side = 4 × 12 = 48 m
Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m
Hence, difference in their perimeters = 50 – 48 = 2 m
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