Question

A rectangle is 16 m by 9 m.Find the side of the square whose area equals the area of the rectangle.By how much does the perimeter of the rectangle exceed the perimeter of the square?

Answer 1

Area of rectangle = length*breadth
= 16*9 =144 square meters
It is given that the area of square equals the area of rectangle
the area of square = 144
side = 12 meters
perimerer of rectangle= 2(l+b)
2(16+9)
= 50 meters
perimeter of square = 4*side
=4*12
=48 meters
thus its perimeter exceeds = 50-48= 2m
It exceed by 2
hope it helps..

Answer 2

Area of rectangle = (16 × 9) m2 = 144 m2

Given condition,

Area of square = Area of rectangle

∴ (Side)2 = 144

Side = √144 = 12 m

Now,

Perimeter of square = 4 × side = 4 × 12 = 48 m

Perimeter of rectangle = 2(l + b) = 2 (16 + 9) = 50 m

Hence, difference in their perimeters = 50 – 48 = 2 m