A rectangle is 16m by 9m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?
Answers
Step-by-step explanation:
Area of rectangle =L×b
=16×9=144m²
We know that the area of rectangle =area of square
So,
Area of square =144m²
Area of square=s²
144=s²
√144=s
12m=s
Perimeter of rectangle =2(l+b)=2(16+9)=50m
Area of square=4×s=4×12=48cm
Difference between the perimeters=50-48=2cm
The perimeter of rectangle exceed the perimeter of dquare by 2cm
Answer:
Length of rectangle = 16m
Width of rectangle = 9m
Area of rectangle = length x width = 16x9 = 144 sq. M.
Area of rectangle = Area of square
So,
Area of square = 144 sq. m.
So, the side of square = √144 = 12m
Length of rectangle = 16m
Width of rectangle = 9m
Perimeter of rectangle = 2 x (length + breadth) = 2 x (16+9) = 2 x 25= 50m
side of square = 12m
Perimeter of square = 4 x side = 4 x 12 = 48m
the perimeter of the rectangle exceeds the perimeter of the square by 50 - 48 = 2m
2m
Step-by-step explanation:
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