Question

A rectangle is 16m by 9m. Find a side of the square whose area equals the area of the rectangle. By how much does the perimeter of the rectangle exceed the perimeter of the square?

Answer 1

Answer:

Step-by-step explanation:

Area of rectangle = l*b

=> 16*9

=> 144m²

ATQ,

Area of square = Area of rectangle

So, Area of square = Side²

=> 144 = Side²

=> 12m = Side

Now, perimeter of square = 4*side

=> 4*12 = 48m

Perimeter of rectangle = 2(l+b)

=> 2(16+9) = 2(25) = 50m

Difference between perimeter = 2m

Thus, the perimeter of rectangle exceeds perimeter of square by 2m.