Question

A rectangle is 2.8cm wide and the length of each diagonal is 5.3cm. Calculate the length of the rectangle

Answer 1

(diagonal)^2 = length ^2+ breadth^2. length = ✓ 28.09+7.84= ✓ 35.93= 5.99 cm

Answer 2

Answer:

4.5cm = length

12.6cm = area

Step-by-step explanation:

using the pythagorean theorem, a^2 + b^2 = c^2

you let the length of the diagonal, 5.3cm be the 'c'

let the width 2.8cm be the 'a'

substitute it on the formula:

c^2 = a^2 + b^2

(5.3)^2 = (2.8)^2 + b^2

28.09 = 7.84 + b^2

transpose:

28.09 - 7.84 = b^2

20.25 = b^2

eliminate the square by square root

√20.25 = √b^2

4.5 = b

b = length of your rectangle.

using the original formula in solving for the area

A = l x w

A = 4.5 x 2.8

A = 12.6