Question

A rectangle is 22 m long and 12 m wide .From its four corner, quadrents of radius 2.5 m have been cut . Find the area of the remaining part .

Answer 1

here is your
$\huge\boxed{\red{\bold{solution}}}$

Given

A rectangle is 22 m long and 12 m wide.
Quadrents of radius 2.5 m

Now ,

Area of rectangle ABCD =length ×breadth
= 22m×12m
$264m {}^{2}$
$area \: of \: quadrant = \frac{1}{4} \times area \: of \: circle \\ = \frac{1}{4} \times \pi \times r {}^{2} \\ = \frac{1}{4} \times \pi\times \frac{22}{10} \times \frac{25}{10} \\ = \frac{25\pi}{16}$
$area \: of \: 4th \: quadrant = 4 \times \frac{25\pi}{16} \\ = \frac{25\pi}{4}$
area of remaining part
$area \: of \: rectangle - area \: of \: 4th \: quadrant \\ = 264 - \frac{25\pi}{4} \\ = 264 - \frac{25 \times 22}{7 \times 4} \\ = 264 - \frac{275}{14} \\ = \frac{3696 - 275}{14} \\ = \frac{3421}{14} \\ = 244 \frac{5}{14} m {}^{2}$
I hope it helps you