Question

A rectangle is 5 cm wide and it area is 35 sq.cm. What is the perimeter of the rectangle?
Pls answer with steps.

Answer 1

Answer:

area of rectangle=35

let length of rectangle be x

5×x=35

x=7

so length of rectangle comes out to be 7

and width is given as 5

so perimeter=2(l+b)

=2(12)=24cm is ur answer

Answer 2

$\begin{gathered}\Large{\bold{\pink{\underline{Formula \: Used \::}}}} \end{gathered}$

$\bigstar \: \: { \boxed{ \red{ \tt \: Area_{(rectangle)} = Length \times Breadth}}}$

$\bigstar \: \: { \boxed{ \red{ \tt \: Perimeter_{(rectangle)}=2(Length + Breadth}}}$

$\large\underline\purple{\bold{Solution :- }}$

$\begin{gathered}\begin{gathered}\bf \: \green{Given}\: -\begin{cases} &\sf{Breadth = 5 \: cm} \\ &\sf{Area_{(rectangle)} = 35 \: {cm}^{2} } \end{cases}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\bf \: \blue{To\:find} \:-\begin{cases} &\sf{Perimeter_{(rectangle)} \: = \: ? }  \end{cases}\end{gathered}\end{gathered}$

It is given that

• Area of rectangle = 35 sq. cm

• Breadth = 5 cm

So,

• Using formula of area of rectangle,

we have

$\rm :\implies\:Area_{(rectangle)} = Length \times Breadth$

$\rm :\implies\:35 = 5 \times Length$

$\bigstar \: \: { \large\boxed{ \green{ \tt \:Length = 7 \: cm }}}$

Now,

We have

• Length of rectangle = 7 cm

• Breadth of rectangle = 5 cm

So,

• Perimeter of rectangle is given by

$\rm :\implies\:Perimeter_{(rectangle)}=2(Length + Breadth)$

$\rm :\implies\:Perimeter_{(rectangle)}=2 \times (7 + 5)$

$\rm :\implies\:Perimeter_{(rectangle)}=2 \times 12$

$\bigstar \: \: { \boxed{ \red{ \bf \implies\:Perimeter_{(rectangle)}=24 \: cm}}}$