Question

A rectangle is made of a thin
were whose length is 16 m and
the width is 4m. the wire is
reshaped to make square. find
its perimeter​

Answer 1

Answer:

i dont understand

Step-by-step explanation:

Answer 2

$\color{red} \large\mathbb{Given}$

Rectangle:-

Length = 16 m

Breadth = 4 m

$\color{green} \large\mathbb{To \: \: {\mathbb{find :-}}}$

Length of square

Area of a square

So, according to the question:-

Perimeter of rectangle is

$\large\color{purple}{\boxed{\mathtt{\leadsto{Perimeter = 2(l+b)}}}}$

$\mathtt{\implies{Perimeter = 2(16 + 4)}}$

$\mathtt{\implies{Perimeter = 2(20)}}$

$\color{blue}\mathtt{\implies{Perimeter = 40 \: cm}}$

Length of a square is :-

$\large\color{purple}{\boxed{\mathtt{\leadsto{Length = \frac{Perimeter \: \: of \: \: rectangle }{4} }}}}$

$\mathtt{\implies{Length = \frac{40}{4} }}$

$\color{blue}\mathtt{\implies{Length = 10}}$

Therefore ,area of the square is :-

$\color{purple}\Large{\boxed{ \mathtt{\leadsto{Area = Side²}}}}$

$\Large{{ \mathtt{\leadsto{Area = {10}^{2} }}}}$

$\color{blue}{ \boxed{\Large{{ \mathtt{\leadsto{Area =100 \: {cm}^{2} }}}}}}$

Therefore, area of square is 100 cm²