Question

a rectangle is made up of three identical rectangles as shown in the figure find the width of each rectangle if length of the largest rectangle is 9cm and its area is 34sqcm.,,,

Answer 1

Answer:

Solution:

Length= 40cm

Breadth= 22cm

Perimeter of the rectangle= Length of the wire

=2(l+b)= 2(40cm + 22cm)

=2\times622×62cm = 124cm

Now, the wire is rebent into a square.

Perimeter= 124cm

4\times side=1244×side=124

Therefore side= \frac{124}{4}4124cm= 31cm

So, the measure of each side= 31cm

Area of rectangular shape= l\times bl×b

=40cm\times22cm40cm×22cm

=880cm^2880cm2

Area of a square shape= \left(Side\right)^2(Side)2

=\left(31\right)^2=961cm^2(31)2=961cm2

Since 961cm^2\ >\ 880cm^2961cm2 > 880cm2

Hence, the square encloses more area.