Question

A rectangle is of area 64sq cm .its breadth is 4cm.find its perimeter

Answer 1

Hey mate here is your answer.

Let the lenght be x.

A/q l x b = area

so, x X 4 cm = 64sq cm

x= 64sq cm = 16 cm

4cm

then, perimeter = 2(l+b)

=> 2(16+4)

=> 2x 20

=> 40 cm Ans

Hope it will help you.

Please mark it as brainlist

Answer 2

Here is your answer :-⭐

A/q_
Area of rectangle = 64sq cm

Breadth = 4cm.

$area \: of \: rectangle = l \times b \\ \\ 64 = l \times 4 \\ \\ \frac{64}{4} = l \\ \\ l = 16cm$


Now,

$perimeter \: of \: rectangle \\ = 2(l + b) \\ \\ = 2(16 + 4) \\ \\ = 2 \times 20 \\ \\ = 40cm \: \: answer$


Hope it helps!!

Please mark brainliest if helpful..

RAASHI❤❤