Question

A rectangle is surrounded by two sets of congruent trapeziums as shown in the adjacent figure.Find the area covered by each? ​

Answer 1

Solution:

height of trapezium ABFE = 20-16/2=4/2=2cm

similarly heights of other trapezium is 2 cm

area of ABEF and CDHG =

$\frac{1}{2} \times (x + y) \times h \\ = \frac{1}{2} \times (18 + 14) \times 2 \\ = 32 \: {cm}^{2}$

area of BFGC and EHDA =

$= \frac{1}{2} \times (x + y) \times h \\ = \frac{1}{2} \times (16 + 20) \times 2 \\ = 36 \: {cm}^{2}$

hope it helps you

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