Question

A rectangle is to be constructed with perimeter 70cm and area 300cm^2 . What are the length of sides

Answer 1

Answer:

Area = l x b

300=lb

l=300/b

P=2(l+b)

70=2(l+b)

l+b=35

put. value of l

300/b+b=35

300+2b/b=35

300=35b-2b

300=33b

b=300/33 =9.09

l=300/9.09

=33.4

Answer 2

Step-by-step explanation:

$perimeter \: of \: rectangle = 2(length + breadth) = 70cm \\ l + b = 35 \: \: - (1)\\ area \: of \: rectangle = length \times breadth = 300 {cm}^{2} \\ l \times b = 300 \: \:- (2)$

$from(1) \\ l = 35 - b \: \: - (3) \\ put \: eq.(3)in \: (2) \\ (35 - b) \times \: b = 300 \\ 35b - {b }^{2} = 300$

$b = 15 \\ put \: in \: eq.(3) \\ l = 35 - 15 \\ l = 20$

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