Question

A rectangle is twice as long as it is wide and it has perimeter of 42 cm. find its length and width. ( note: the topic is simultaneous linear equation and solution should be of comparison method)

Answer 1

Answer:

let length of rectangle be 2x and width be x

Step-by-step explanation:

A/q    2(2x+x)=42

  =>   6x=42

  =>   x=7

                            length=14cm

                            width=7cm

Answer 2

solution:-)

Let the width of a rectangle is x .

Then , the length of a rectangle be 2x .

We know that :-

According to question :-

2(2x+ x ) = 42

=> 4x + 2x = 42

=> 6x = 42

=> x = 42/6

=> x = 7

Putting x = 7

Then , length = 2x = 2×7 = 14