Question

A rectangle is with length 50 cm and Breadth 25 cm . Find the Perimeter and Area of the Rectangle​

Answer 1

Answer :

• Perimeter of rectangle = 150cm

• Area of rectangle = 1250cm²

Step-by-step explanation :

To Find,

• Perimeter of rectangle

• Area of rectangle

Solution,

Given that,

• Length of rectangle = 50 cm

• Breadth of rectangle = 25 cm

The perimeter of rectangle is,

As we know that,

Perimeter = 2 ( l + b )

Where,

• l = Length
• b = Breadth

➠ Perimeter = 2 ( l + b )

➠ 2 ( 50 + 25 )

➠ 2 × 75

➠ 150

The perimeter of rectangle is 150cm.

The area of rectangle is,

As we know that,

Area = ( l × b )

Where,

• l = Length
• b = Breadth

➠ Area = l × b

➠ 50 × 25

➠1250

The area of rectangle is 1250cm².

Answer 2

Question:

A rectangle is with length 50 cm and Breadth 25 cm . Find the Perimeter and Area of the Rectangle

To find:

• Perimeter of rectangle
• Area of rectangle

Given :

• Length of rectangle = 50 cm
• Breadth of rectangle = 25 cm

Solution :

Part 1:

To find perimeter of rectangle

We know:

$\pink \bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2 \times (length + breadth)}$

By using this formula we can find value of Perimeter

$: \implies\sf Perimeter \: of \: rectangle = 2 \times (length + breadth)$

Put values of length and breadth

$: \implies\sf Perimeter \: of \: rectangle = 2 \times (50+ 25)$

$: \implies\sf Perimeter \: of \: rectangle = 2 \times (75)$

$: \implies \underline{ \boxed{\sf Perimeter \: of \: rectangle =150 \: cm}}$

Part 2:

To find area of rectangle :

$\pink \bigstar \boxed{ \rm Area\: of \: rectangle =length \times breadth}$

By using this formula we can find value of Area.

$: \implies\sf Area\: of \: rectangle =length \times breadth$

Put values of length and breadth

$: \implies\sf Area\: of \: rectangle =50\times 25$

$: \implies \underline{ \boxed{\sf Area\: of \: rectangle =1250 {cm}^{2} }}$

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☆Know More ☆

Formulas for area:

• $\tt{}Area \: of \: square = {side}^{2}$

• $\tt{}Area \: of \: triangle = \dfrac{1}{2} \times base \times height$

• $\tt{}Area \: of \: trapezium = \dfrac{base_1 + base_2}{2} \times height$

• $\tt{}Area \: of \: cylinder=2\pi rh+2\pi {r}^{2}$

• $\tt{}Area \: of \: sphere=4\pi {r}^{2}$

• $\tt{}Area \: of \: rhombus= \dfrac{Digonal_1+Digonal_2}{2}$

Formulas for Perimeter:

• $\tt{}Perimeter \: of \: square = 4\times side$

• $\tt{}Perimeter \: of \: triangle = Side_1+Side_2+Side_3$

• $\tt{}Perimeter \: of \: trapezium = Side_1+Side_2+Side_3+Side_4$

• $\tt{}Perimeter \: of \: Circle=2\pi r$

• $\tt{}Perimeter \: of \: rhombus= 4\times side$

And all we are done! ✔

:)