Question

A rectangle is with length 50 cm and Breadth 25 cm . Find the Perimeter and Area of the Rectangle​

Answer 1

Step-by-step explanation:

Perimeter of Rectangle=2(l+b)

.

2(50+25)

2(75)

Perimeter=150cm

Area of Rectangle=l×b

=>1250cm^2

Answer 2

$\large\underline{ \underline{ \sf \maltese\red{ \: Question:- }}}$

• A rectangle is with length 50 cm and Breadth 25 cm . Find the Perimeter and Area of the Rectangle

$\large\underline{ \underline{ \sf \maltese\pink{ \: Given:- }}}$

• Length of Rectangle = 50cm
• Breadth of Rectangle = 25cm

$\large\underline{ \underline{ \sf \maltese\blue{ \: Diagram:- }}}$

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 25 cm}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 50 cm}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}$

$\large\underline{ \underline{ \sf \maltese\green{ \: Solution:- }}}$

$\underbrace\red{\boxed{ \sf \blue{ Perimeter \: of \: Rectangle }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Perimeter \: of \: Rectangle\: = \: 2( Length \: + \: Breadth ) }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:}\longrightarrow\sf{\sf\ \: 2( \: 50 \: + \: 25 \: ) }$

$\qquad \quad {:}\longrightarrow\sf{\sf\ \: 2\: \times \: 75 }$

$\qquad \quad {:}\longrightarrow\sf{\sf\ \: 150cm}$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Perimeter \: = \: 150cm }}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\underbrace\red{\boxed{ \sf \blue{ Area\: of \: Rectangle }}}$

$\begin{gathered}\begin{gathered}\begin{gathered}: \implies \underline\blue{ \boxed{\displaystyle \sf \bold\orange{\: Area \: of \: Rectangle\: = \: Length \: \times \: Breadth }} }\\ \\\end{gathered}\end{gathered}\end{gathered}$

$\qquad \quad {:}\longrightarrow\sf{\sf\ \: 50 \: \times \: 25 \:}$

$\qquad \quad {:}\longrightarrow\sf{\sf\ \:1250cm }$

$\qquad\quad {:} \longrightarrow \underline \red{\boxed{\sf{Area \: = \: 1250cm ^{2} }}}$

━━━━━━━━━━━━━━━━━━━━━━━━━

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Perimeter \: of \: Rectangle \: = \underline {\underline{ 150cm}}}\\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\qquad \therefore\: \sf{ Area\: of \: Rectangle \: = \underline {\underline{ 1250cm^2}}}\\\end{gathered}\end{gathered}$

━━━━━━━━━━━━━━━━━━━━━━━━━