A rectangle length is 5cm less than twice its width.If the length is decreasedby 2cm. The perimeter of the resulting rectangle will be 74cm. Find the length and width of the original rectangle.
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Let breadth be ' b'
Length of rectangle l =(2b-5) cm
if the length is decreased by 2cm then
perimeter of rectangle=74 cm
2(l+b) =74
l+b =37
2b-5-2+b=37
3b-7=37
3b=42
b=42/3=14 cm
length =2(14)-5
l =23 cm
Length of rectangle l =(2b-5) cm
if the length is decreased by 2cm then
perimeter of rectangle=74 cm
2(l+b) =74
l+b =37
2b-5-2+b=37
3b-7=37
3b=42
b=42/3=14 cm
length =2(14)-5
l =23 cm
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