A rectangle measures 15cm by20cm find the angle between its diagonal
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Let ABCD is a rectangle in which AB=CD=15cm ,BC=DA=20cm , and B is on origin , Coordinate of B (0,0) , A(0,15) ,C(20,0) and D(20,15).
Slope of diagonal BD(m1)=(15–0)/(20–0)=3/4
Slope of diagonalAC(m2)=(0–15)/(20–0)-3/4
let p be the angle between diagonals.
tan p=(m1-m2)/(1+m1.m2)
tan p=(3/4+3/4)/(1–9/16)
tan p=(6/4)/(7/16)
tan p=6/4×16/7=24/7
p= tan inverse (24/7) , Answer.
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