A rectangle measures 8 cm by 6 cm. On the shorter sides two equilateral triangles are constructed
outside the rectangle.Two right-angled isosceles triangles are constructed outside the rectangle with
the longer sides as the hypotenuse. Find the total area and perimeter of figure.
Answers
we draw this diagram by given information
Step-by-step explanation:
Here ABCD is a rectangle , AB = CD = 8 cm and BC = AD 6 cm
And
BCE and ADG are equilateral triangle , BC = BE = CE = AD = AG = DG = 6 cm
And
ABH and CDF are right angled isosceles triangle , Hypotenuse AB = CD = 8 cm , Let AH = BH = CF = DF = x
Now we apply Pythagoras theorem in triangle ABH and get
AH 2 + BH2 = AB2
x 2 + x 2 = 82
2 x 2 = 64
x 2 = 32
x = 32−−√
x = 4 2√
So,
AH = BH = CF = DF = 4 2√
We know Area of rectangle = Length × Breadth , So
Area of ABCD = 8 × 6 = 48 cm2
And
Area of triangle = 12 × Height × Base , So
Area of triangle ABH = Area of triangle CDF = 12 × 4 2√× 4 2√ = 16 cm2
And
Area of equilateral triangle = 3√4×(Side)2 , So
Area of triangle BCE = Area of triangle ADG = 3√4×(6)2 = 3√4×36 = 93√ = 9 × 1.732= 15.588 ≈ 15.59 cm2
So,
Area of our figure AHBECFDG = Area of ABCD + Area of triangle ABH + Area of triangle CDF + Area of triangle BCE + Area of triangle ADG
Area of our figure AHBECFDG = 48 + 16 + 16 + 15.59 + 15.59 = 111.18 cm2 ( Ans )
Perimeter of our figure AHBECFDG = AH + BH + BE + CE + CF + DF + DG + AG = 4 2√ + 4 2√ + 6 + 6 + 42√ + 4 2√ + 6 + 6 = 24 + 162√ = 24 + 22.63 = 46.63 cm
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Step-by-step explanation:
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