Math, asked by pragya1565, 6 months ago

A rectangle measures 8 cm by 6 cm. On the shorter sides two equilateral triangles are constructed
outside the rectangle.Two right-angled isosceles triangles are constructed outside the rectangle with
the longer sides as the hypotenuse. Find the total area and perimeter of figure.​

Answers

Answered by Kshitu73
12

we draw this diagram by given information

Step-by-step explanation:

Here ABCD is a rectangle , AB = CD = 8 cm and BC = AD 6 cm

And

BCE and ADG are equilateral triangle , BC = BE = CE = AD = AG = DG = 6 cm

And

ABH and CDF are right angled isosceles triangle , Hypotenuse AB = CD = 8 cm , Let AH = BH = CF = DF = x

Now we apply Pythagoras theorem in triangle ABH and get

AH 2 + BH2 = AB2

x 2 + x 2 = 82

2 x 2 = 64

x 2 = 32

x = 32−−√

x = 4 2√

So,

AH = BH = CF = DF = 4 2√

We know Area of rectangle = Length × Breadth , So

Area of ABCD = 8 × 6 = 48 cm2

And

Area of triangle = 12 × Height × Base , So

Area of triangle ABH = Area of triangle CDF = 12 × 4 2√× 4 2√ = 16 cm2

And

Area of equilateral triangle = 3√4×(Side)2 , So

Area of triangle BCE = Area of triangle ADG = 3√4×(6)2 = 3√4×36 = 93√ = 9 × 1.732= 15.588 ≈ 15.59 cm2

So,

Area of our figure AHBECFDG = Area of ABCD + Area of triangle ABH + Area of triangle CDF + Area of triangle BCE + Area of triangle ADG

Area of our figure AHBECFDG = 48 + 16 + 16 + 15.59 + 15.59 = 111.18 cm2 ( Ans )

Perimeter of our figure AHBECFDG = AH + BH + BE + CE + CF + DF + DG + AG = 4 2√ + 4 2√ + 6 + 6 + 42√ + 4 2√ + 6 + 6 = 24 + 162√ = 24 + 22.63 = 46.63 cm

hope it will help you

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Answered by Anonymous
3

Step-by-step explanation:

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