Question

A rectangle measures 8 cm on its lenth. It's diagonal is 10 cm. What is the perimeter of the rectangle?​




Answer it and you will got 100 po
ints​

Answer 1

$\underline {\bf \huge \: Answer }$

From the formula of Diagonal,

$\sqrt{ \sf \: lenghth^{2} + breadth^{2} } = \sf \: diagonal$

Therefore,

$\sqrt{ {8}^{2} + \sf \: {breadth}^{2} } = {10}^{2}$

$\sf \: \sqrt{ 64 + \sf \: {breadth}^{2} } = 100$

Squaring both sides,

$\sf \: breadth^{2} = 100 - 64$

$\sf \: breadth^{2} = 36$

Applying square root on both sides,

$\sf \: breadth = 6$

_____________________________

Breadth = 6cm

Answer 2

Answer:

The breadth will be 6cm

Length is 10cm

The perimeter will be 32cm

Hope it helps

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