Question

a rectangle of length 42cm and breadth 28cm or a square of side 39 cm which has larger area and by how much ?

Answer 1

area of a rectangle= l×b=42×28= 1176 cm²

area of a square= s×s or s²=39×39 or 39²= 1521 cm²

therefore the area of the square is larger than the area of the rectangle by (1521-1176=) 345 cm²

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Answer 2

SOLUTION :

The length of the rectangle = 42 cm

and breadth of the rectangle = 28 cm

The each side of  the square is 39 cm

To be found :-

Whose area is larger and by how much

Area of rectangle = lb  unit sq. [ ∴ in which l is the length and b is the breadth of the rectangle ]

Area of rectangle = 42 × 28  cm sq.

Area of rectangle = 1176 cm sq.

∴ Area of the rectangle = 1176 cm sq.

Now,

Area of square = $\bf {(a)}^{2} }$ unit sq.

Area of square =  $\bf {(39)}^{2} }$ cm sq.

Area of square = 1521 cm sq.

∴ Area of the square = 1521 cm sq.

Now,

Comparing the areas of both rectangle and square

( Area of square = 1521 cm sq. ) > ( Area of rectangle = 1176 cm sq. )

Hence,

The area of square is greater by area of rectangle by,

1521 - 1176 = 345 cm sq.