Question

A rectangle of length 50 m and width 30 m was to be fenced along the boundaries. Find the

perimeter of another rectangle of twice the length and half the width of the given rectangle.​

Answer 1

here is your answer mate....

the length of new rectangle will be 100 m and breadth = 15m

then perimeter will be...

2(100+15) = 230 m

Answer 2

Answer:

The perimeter of the new rectangle is 230m

Step-by-step explanation:

Old rectangle

The length of a rectangle is 50m

The width of the rectangle is 30m

Now, in new rectangle

The length of a rectangle is doubled

Therefore, the length of the new rectangle is 100m

The width of the rectangle is halved

Therefore, the width of the new rectangle is 15m

So,

$Perimeter\ of\ rectangle =2(l+b)$

Perimeter of new rectangle = 2(100+15)m

The perimeter of new rectangle = 230m

Therefore, the perimeter of the new rectangle is 230m