Question

A rectangle of length 50 metres and width 30 metres was to be fenced along the boundaries. Find the perimeter of another rectangle of twice the length and half the width of the given rectangle.​

Answer 1

Answer:

$\huge\fbox\red{Answer}$

Step-by-step explanation:

L = 50m B = 30m

length 1=2x50 breadth=1/2x30

perimeter = 2(100+15)

=230m

Hope it helps uh ♡

#✰ ᎷỉʂʂHєαятHα¢кєя ✰

Answer 2

length -1=2*50

breadth -1= 2*50

breadth = 1/2 *30

perimeter= 2(100+15)

= 230 m answer