Question

A rectangle of length 8 cm and diagonal 10 cm find its area. Step-by-step answer only please…​

Answer 1

Answer:

Area of a rectangle is 48 sq.cm

Step-by-step explanation:

Given ;

Length of the Rectangle = 8 cm

Diagonal of the Rectangle = 10 cm

Area of a rectangle = L × √ d2 - L2

( A ) = L × √ d×d - L×L

A = 8 × √ 100 - 64

A = 8 × √ 36

A = 8 × 6

Hence ;

Area of the Rectangle = 48 sq.cm

Answer 2

In context to questions asked,

We have to determine the value of area of rectangle.

As per questions,

We have,

Length of rectangle = 8 cm

Diagonal of rectangle = 10 cm

So, by using Pythagoras theorem,

We will get the breadth of rectangle as,

$\sqrt{ {10}^{2} - {8}^{2} } \\ = > \sqrt{100 - 64} \\ = > \sqrt{36} \\ = > 6 \: cm$

As we know that,

Area of rectangle will be,

$Area \: = 8 \times 6 = 48 \: {cm}^{2}$