Question

A rectangle of perimeter 74cm is 7cm longer than it is wide what is the length of each side

Answer 1

Answer:

2(x+x+7)=74

2(2x+7)=74

2x+7=37

2x=30

x=15

Answer 2

Question:

A rectangle of perimeter 74cm is 7cm longer than it is wide what is the length of each side.

To find:

$Length \: of \: rectangle = ?$

Answer:

$Length \: of \: rectangle \: is \: \underline{ \: \underline{ \: \sf \pink{\bold{22cm}} \: } \: }$

Given:

$Perimeter \: of \: rectangle = 74cm$

$Breadth \: of \: rectangle(b) = x \: cm$

$Length \: of \: rectangle(l) = x + 7cm$

Step-by-step explanation:

$\boxed{Perimeter \: of \: rectangle = 2(l + b)}$

$\implies 2(x + 7 + x) = 74$

$\implies 2(2x + 7) = 74$

$\implies 2x + 7 = 37$

$\implies 2x = 30$

$\implies \boxed{x = 15}$

$Breadth = x = 15cm$

$\boxed{Breadth \: of \: rectangle = 15cm}$

$Length = x + 7 = 15 + 7 = 22cm$

$\boxed{Length \: of \: rectangle = 22cm}$

Formula used:

$\bigstar {Perimeter \: of \: rectangle = 2(l + b)}$

Hint:

Hint given in the question:-

$\bigstar Wide = x cm$

$\bigstar 7cm\:longer \:than \:it\: is \:wide = x + 7 cm$

$\therefore Length\: is\: x + 7 cm$