A rectangle of sides 8cm and 6cm is inscribed in the circle. Find the area of remaining part of the circle. (use = 3.14)
Answers
Answer:
area of rectangle = 8×6= 48cm2
since circle s diameter = 6cm
radius = 3cm
area of the circle = pye r2
= 3.14 × (3)^2
= 3.14 × 9 = 28.26ans
Step-by-step explanation:
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Answer:
30.5 cm²
Step-by-step explanation:
Length of the rectangle=8 cm
Breadth of the rectangle=6 cm
Area = length*breadth
Area = 8*6 = 48 cm²
We know, that the diagonal of the rectangle is the diameter of the circle.
That particular diagonal divides the rectangle into 2 congruent right triangles.
So, by Pythagoras Theorem,
8²+6²=diagonal²
⇒36+64 = d²
⇒d=√100
⇒d = 10 cm
Now, the diameter of the circle is 10 cm. So, the radius of the circle = 10/2 = 5 cm.
Area of the circle = πr²
= 3.14*5*5
= 78.5 cm²
Area of the remaining part of the circle = area of the circle - area of the rectangle.
Area of the remaining part of the circle = 78.5 - 48
Area of the remaining part of the circle = 30.5 cm².