Math, asked by pranitmade7681, 11 months ago

A rectangle of sides 8cm and 6cm is inscribed in the circle. Find the area of remaining part of the circle. (use = 3.14)

Answers

Answered by makhandebnath36384
0

Answer:

area of rectangle = 8×6= 48cm2

since circle s diameter = 6cm

radius = 3cm

area of the circle = pye r2

= 3.14 × (3)^2

= 3.14 × 9 = 28.26ans

Step-by-step explanation:

mark me brainly plzz....

Answered by AdorableMe
2

Answer:

30.5 cm²

Step-by-step explanation:

Length of the rectangle=8 cm

Breadth of the rectangle=6 cm

Area = length*breadth

Area = 8*6 = 48 cm²

We know, that the diagonal of the rectangle is the diameter of the circle.

That particular diagonal divides the rectangle into 2 congruent right triangles.

So, by Pythagoras Theorem,

8²+6²=diagonal²

⇒36+64 = d²

⇒d=√100

⇒d = 10 cm

Now, the diameter of the circle is 10 cm. So, the radius of the circle = 10/2 = 5 cm.

Area of the circle = πr²

                             = 3.14*5*5

                             = 78.5 cm²

Area of the remaining part of the circle = area of the circle - area of the rectangle.

Area of the remaining part of the circle = 78.5 - 48

Area of the remaining part of the circle = 30.5 cm².

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