A rectangle piece of paper measure 60 cm by 46 cm. When it's placed on a table if leaves a margin 4 cm wide around it. What is the area of a table top not covered by the paper?
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Answered by
1
Answer:
Step-by-step explanation:
Let ABCD denotes the rectangular sheet.
Length of sheet = 30 cm
Breadth of sheet = 20 cm
∴ Area of sheet = Length × Breadth
= (30 × 20) cm2
= 600 cm2
4 cm wide strip is cut from rectangular sheet all around, then we obtain a rectangular sheet PQRS, having
Length = (30 – (4 + 4)) cm = 22 cm
Breadth = (20 – (4 + 4)) cm = 12 cm
∴ Area of remaining sheet PQRS = (22 × 12) cm2 = 264 cm2
∴ Area of strip cutout = Area of sheet ABCD – Area of sheet PQRS
= (600 – 264) cm2
= 336 cm2
Hope this helps!
Answered by
0
area of rec ppr = 60×40=2400sq.unit
now lenght of table =60+4+4=68
breadth=40+4+4=48
now, area of table=68×48=3264sq.unit
now, area not covered=ar. of table -ar. of ppr
=3264-2400
=864sq.unit
now lenght of table =60+4+4=68
breadth=40+4+4=48
now, area of table=68×48=3264sq.unit
now, area not covered=ar. of table -ar. of ppr
=3264-2400
=864sq.unit
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