Question

A rectangle's length is 12 inches greater than its width. If the perimeter of the rectangle is 44 inches, find the length. (all answers are given in inches.)

Answer 1

Answer:

let breadht = x

length=12+x

2(x+12+x)=44

2(2x+12)=44

2x+12=22

2x=10

x=5

lenght=17 inches

Answer 2

The length of the rectangle is 17 inches.

Step-by-step explanation:

Given : A rectangle's length is 12 inches greater than its width. If the perimeter of the rectangle is 44 inches.

To find : The length ?

Solution :

Let the width of the rectangle is 'w'.

A rectangle's length is 12 inches greater than its width.

i.e. l=12+w

The perimeter of the rectangle is $P=2(l+b)$.

$44=2(12+w+w)$

$44=2(12+2w)$

$44=24+4w$

$4w=44-24$

$4w=20$

$w=\frac{20}{4}$

$w=5$

The width is 5 inches.

The length is l=12+5=17 inches.

#Learn more

The length of a rectangle is twice it's breadth.the perimeter of the rectangle is 120cm.find the length and breadth of this rectangle

https://brainly.in/question/8019524