Question

A rectangle' s length is 5cm less than its width.if the length is decresed by 5cm and width is increased by 2cm;find the length and the width of the original rectangle

Answer 1

Let L & W be the original length and width
:
Write an equation for each statement.
:
Length of a rectangle is 5 cm less then twice its breadth,
L = 2W - 5
if the length is decreased by 3 cm and breadth increased by 2 cm the perimeter is 72.
2(L-3) + 2(W+2) = 72
Divide equation by 2
L - 3 + W + 2 = 36
L + W - 1 = 36
L + W = 37
Replace L with (2W-5)
(2W-5) + W = 37
3W = 37 + 5
3W = 42
W = 42/3
W = 14 cm is the original width
Find L
L = 2(14) - 5
L = 28 - 5
L = 23 cm is the original length
:
find the area of original rectangle.
23 * 14 = 322 sq cm