Question

A rectangle sheet of paper is 12 1/2 cm long and 10 2/3 cm wide . Find its perimetre ?​

Answer 1

Step-by-step explanation:

Given ;-

⇒ Length of the rectangle sheet = 12   1 / 2  cm

⇒Breadth of the rectangle sheet = 10    2 / 3 cm

To find :-

⇒Perimeter = ?

Sol ;- 

⇒ Perimeter of rectangle  =         2   (  l  +  b  )

                                         ⇒   {  2  ( 25 / 2  + 32  /3  }

                                         ⇒  {   2  ( 75 / 6  +  64  /  6  } 

                                         

                                         ⇒ 2 × 139 /  6  

 

                           

                                         ⇒   139   /  3  = 3 1/46  cm

Therefore the answer is ;- 3   1 /46  cm

Answer 2

$\huge\mathfrak\blue{Answer:}$

Given:

• We have been given a rectangle
• Dimensions are $\sf{12 \: \dfrac{1}{2}}$ and $\sf{10 \: \dfrac{2}{3}}$ which are given in cm

To Find:

• We have to find the perimeter of Given rectangle

Solution:

We have been given that in a rectangle

$\boxed{\sf{Length = 12 \: \dfrac{1}{2}= \dfrac{25}{2} cm}}$

$\boxed{\sf{Breadth = 10 \dfrac{2}{3}= \dfrac{32}{3} cm}}$

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$\underline{\large\mathfrak\orange{Finding \; the \: Perimeter:}}$

$\implies \boxed{\sf{\pink{Perimeter = 2 \: ( Length + Breadth ) }}}$

$\implies \sf{Perimeter = 2 \: \left ( \dfrac{25}{2} + \dfrac{32}{3} \right ) }$

Taking LCM inside Braket

$\\ \implies \sf{2 \: \left ( \dfrac{25 \times 3 + 32 \times 2 }{6} \right ) }$

$\implies \sf{ 2 \: \left ( \dfrac{75 + 64}{6} \right ) }$

$\implies \sf{2 \times \dfrac{139}{6} }$

$\implies \sf{\cancel{2} \times \dfrac{139}{\cancel{6}} }$

$\implies \sf{\dfrac{139}{2} }$

$\implies \sf{69.5 cm }$

Hence perimeter is 69.5 cm

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$\huge\underline{\sf{\red{A}\orange{n}\green{s}\pink{w}\blue{e}\purple{r}}}$

$\large\boxed{\mathfrak\purple{Perimeter \: of \: Rectangle = 69.5 \: cm }}$

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