Question

a rectangle surface has length 4661m tiles breadth 3318m on this area square tiles are to be put. find the maximum length of tiles.
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Answer 1

Step-by-step explanation:

Here, 4661 > 3318 So, we divide 4661 by 3318 By using Euclid’s division lemma, we get 4661 = 3318 × 1 + 1343 Here, r = 1343 ≠ 0. On taking 3318 as dividend and 1343 as the divisor and we apply Euclid’s division lemma, we get 3318 = 1343 × 2 + 632 Here, r = 632 ≠ 0 So, on taking 1343 as dividend and 632 as the divisor and again we apply Euclid’s division lemma, we get 1343 = 632 × 2 + 79 Here, r = 79 ≠ 0 So, on taking 632 as dividend and 79 as the divisor and again we apply Euclid’s division lemma, we get 632 = 79 × 8 + 0 The remainder has now become 0, so our procedure stops. Since the divisor at this last stage is 79, the HCF of 3318 and 4661 is 79. Hence, the maximum length of such tiles is 79 meters.Read more on Sarthaks.com - https://www.sarthaks.com/919857/rectangular-surface-length-meters-breadth-meters-square-tiles-maximum-length-such-tiles

Answer 2

Answer:

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