Question

A rectangle whose length is 4 m more than its breadth has an area of 45 sq m . Find the length and breadth of the rectangle​

Answer 1

Answer:

Let length = x,

∴L=4+x

Area=(x)(4+x)=45

4x+x

2

=45

x

2

+4x−45=0

(x+9)(x−5)=0

x=5

x=−9 not possible

∴ Length = x+4

= 5+4

= 9

Answer 2

Answer:

Step-by-step explanation:

l=b+4[l=length,b=breadth]

area=lxb

45=(b+4).b(as l=b+4)

$b^{2}$+4b-45=0

if you know quadratic equation solving then you can do this problem

i will tell formula

ax^2+bx+c(general form of quadratic equation)

then

x=-b+or-$\sqrt{b^2-4ac}$/2a

here in same b^2+b-45=0

a=1

b=4

c=-45

breadth=-4+or-$\sqrt{4^2-4.1.-45}$/2

-4+14/2=10/2=5

l=5+4=9