Question

A rectangle whose length is 5x +2 and breath is 3x find the length of rectangle if perimeter of rectangle is 68

Answer 1

Answer:

p=2(l+b)

68=2(5x+2 + 3x)

68=10x +4 +6x

68=16x +4

68-4=16x

64=16x

x=64/16

therefore x=4

therefore length= 5x+ 2 = 5*4+2 =22

therefore breath= 3x= 3*4= 12

Answer 2

Answer:

The Length of the Rectangle = 22 units.

Step-by-step explanation:

Given, Length of the rectangle = (5x + 2) units

          Breadth of the rectangle = 3x units

          Perimeter of the rectangle = 68 units

We know that,

Perimeter (of rectangle) = 2 * (Length + Breadth)

∴ 68 = 2 * [(5x + 2) + (3x)]

=> 2 * [5x + 2 + 3x] = 68

=> 2 * [8x  + 2] =  68

=> 16x + 4 = 68

=> 16x = 68 - 4

=> 16x = 64

=> x = $\frac{64}{16}$

=> x = 4

∵ The value of x = 4 units

∴ The length = (5x + 2) units

                     = {(5 * 4) + 2} units

                     = (20 + 2) units

                     = 22 units

The breadth = (3 * x) units

                     = (3 * 4) units

                     = 12 units

[NOTE: SINCE THE UNIT IS NOT MENTIONED, THEREFORE TAKING IT AS 'UNITS']

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