Question

a rectangle wire of length 40 cm and breath 20 cm is bent is the shape of a square .find the side of square​

Answer 1

Answer:

Step-by-step explanation:

40×20=600

Side of square=S/4

=600/4

=150

Answer 2

Answer:

Given A wire is in shape of rectangle 

Given A wire is in shape of rectangle where

Given A wire is in shape of rectangle wherelength=20 cm. 

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of square

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cm

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cmnow 

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cmnow Perimeter of rectangle = perimeter of square  

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cmnow Perimeter of rectangle = perimeter of square  64=4a

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cmnow Perimeter of rectangle = perimeter of square  64=4a[a=16cm]

Given A wire is in shape of rectangle wherelength=20 cm. breadth=12 cm.Perimeter of rectangle =2(l+b)=2(32)[Perimeter =64 cm.]now of wire is bent in shape of squarewhere side =a cmnow Perimeter of rectangle = perimeter of square  64=4a[a=16cm]side of square formed is 16 cm.