a rectangle with a length of 9 cm is divided into two smaller rectangle A and B with areas 27 sq.cm and 45 sq.cm find the perimeter of given rectangle
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1
Answer:
Perimeter of rectangle = perimeter of square =80 cm
⇒2(l+b)=45=80
⇒S=
4
80
=20 cm;2(l+b)=80
⇒l+b=40 cm - (1)
difference m areas = 100 cm
2
5
2
−(lb)=100
(20)(20)−(lb)=100
⇒lb=300 - (2)
From (1) and (2)
30+10=40;3×10=l×b
⇒l=30 and b=10
sides of rectangle are 30,10 cm
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