Question

A rectangle with diagonals of length 20 cm has sides in the ratio 2:1 find the area of the rectangle

Answer 1

Answer:

160 cm².

Step-by-step explanation:

• Let the length of rectangle be 2 x cm and breadth be x cm .
• Diagonal = √ l² + b²

A/Q, √ (2 x )² + x²  = 20

⇒ 5 x² = 400

⇒ x² = 80

∴ x = √80 = 4√5.

• Area = l x b = 2 x × x = 2 x²

                         = 2 × 4√5 × 4√5

                        =  160 cm².

Thank u.

Answer 2

Answer:

Step-by-step explanation:

Answer:

Step-by-step explanation:

Let l=2x and b=x

Diagonal of rectangle =20cm

√l²+b²=20

√(2x)²+x²=20

√4x²+x²=20

√5x²=20

(5x²)power1/2=20

5x=20

x=20/5

x=4

Length =2x=2(4)=8cm

Breadth=x=4cm

Area of rectangle=lb=8*4=32cm²