A rectangle with one side 4cmis inscribed in a circle of radius 2•5cm.find the area of rectangle.
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here is the answer for your question
Given, rectangle ABCD is inscribed in a circle of radius 2.5 cm
Let AB = 4 cm
Now, OA = OC = 2.5 cm [Radius of circle]
⇒ AC = OA + OC = 2.5 + 2.5 = 5 cm
In right triangle ABC, by Pythagoras theorem
(AC)2 = (AB)2 + (BC)2
⇒ 52 = 42 + (BC)2
⇒ BC2 = 25 – 16 = 9
⇒ BC = 3 cm
∴ Area of rectangle = AB × BC = 4 × 3 = 12 cm2
Given, rectangle ABCD is inscribed in a circle of radius 2.5 cm
Let AB = 4 cm
Now, OA = OC = 2.5 cm [Radius of circle]
⇒ AC = OA + OC = 2.5 + 2.5 = 5 cm
In right triangle ABC, by Pythagoras theorem
(AC)2 = (AB)2 + (BC)2
⇒ 52 = 42 + (BC)2
⇒ BC2 = 25 – 16 = 9
⇒ BC = 3 cm
∴ Area of rectangle = AB × BC = 4 × 3 = 12 cm2
zayD1:
how should i know (AC)2=52
Answered by
0
5cm^2
A triangle =1/2×bxh=5^2
A triangle =1/2×bxh=5^2
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