A rectangle with one side of length 4cm is inscribed in a circle of radius 2.5cm. find the area of the rectangle
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Answered by
108
Hey!
Given,
Radius of circle = 2.5 cm
Diameter = 2*r = 5 cm
Here, Diameter of rectangle = Diagonal of rectangle = 5 cm
Hence, Sides of triangle formed = 4 cm and 5 cm and x cm
We know,
Pythagoras Theorem ,
i.e H² = B² + P²
5² = x² + 4²
25 = x² + 16
9 = x²
3 = x
Hence sides of rect. = 3 cm, 4 cm
Area = l*b
= 3*4
= 12 cm²
Given,
Radius of circle = 2.5 cm
Diameter = 2*r = 5 cm
Here, Diameter of rectangle = Diagonal of rectangle = 5 cm
Hence, Sides of triangle formed = 4 cm and 5 cm and x cm
We know,
Pythagoras Theorem ,
i.e H² = B² + P²
5² = x² + 4²
25 = x² + 16
9 = x²
3 = x
Hence sides of rect. = 3 cm, 4 cm
Area = l*b
= 3*4
= 12 cm²
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Answered by
20
Answer:
Diagonal of a rectangle = diameter of the circle = 2*2.5=5 cm
Applying Pythagoras theorem in triangle BCA ,
We get ,
AB=3 cm
Since ABCD is a rectangle
AB=DC=3 cm
Area of rectangle =length * breadth =3cm*4cm=12 cm Square
Ans =12 cm Square
Step-by-step explanation:
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