a rectangle with one side of length 4cm is inscribed in a circle of diameter 5 cm.find the area of the rectangle.
Answers
Answered by
3
Let the area be x.
Then it will be x^2 + 4^2 = 5^2
x^2 + 16 = 25
x^2 = 9
x = 3.
Area of the rectangle will be 3×4 = 12 cm^2.
Then it will be x^2 + 4^2 = 5^2
x^2 + 16 = 25
x^2 = 9
x = 3.
Area of the rectangle will be 3×4 = 12 cm^2.
Answered by
3
Given,
Radius of circle = 2.5 cm
Diameter = 2*r = 5 cm
Here, Diameter of rectangle = Diagonal of rectangle = 5 cm
Hence, Sides of triangle formed = 4 cm and 5 cm and x cm
We know,
Pythagoras Theorem ,
i.e H² = B² + P²
5² = x² + 4²
25 = x² + 16
9 = x²
3 = x
Hence sides of rect. = 3 cm, 4 cm
Area = l*b
= 3*4
= 12 cm²
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thatflawsomegirl:
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