Question

A rectangle with perimeter 396 m is divided into five smaller congruent rectangles, as shown in Fig. 4. Find the perimeter of one of the rectangles.​

Answer 1

Answer:

Let b and I be the breadth end length of each small rectangle. Given, perimeter of big rectangle =264cm

According to the figure(in clockwise direction starting from top left corner)

⇒perimeter =b+b+b+l+b+l+l+b+l=264

⇒4l+5b=264⋯⋯(1)

Also, from figure it is clear that 3 breadth of top vertical rectangles is equal to 2 lengths of bottom horizontal rectangles

⇒2l=3b⋯⋯(2)

Now, put the value of 3b into equation 2 from equation 1

⇒4l+5b=2×2l+5b=2×3b+5b=264

⇒(6+5)b=264

⇒b=

11

264

⇒b=24cm

⇒l=

2

3b

=

2

3×24

=36cm

Therefore, perimeter of the rectangle

=2(l+b)

=2(36+24)

=120cm

Answer 2

Answer:

No this is wrong answer thrre is no big rectangle perimeter