Question

A rectangle with perimeter 396m is divided into five smaller congruent rectangle,.find the perimeter of one of the rectangle.​

Answer 1

Answer:

The perimeter of one of the rectangle is 180m.

Step-by-step explanation:

Given:

Perimeter of rectangle = 396m.

To Find:

Perimeter of one of the rectangle ?

Solution:

Let,

Length of each small rectangle be ‘l’.

Breadth of each small rectangle be ‘b’.

According to the condition,

Perimeter = b+b+b+b+l+b+l+l+b+l = 396m

Perimeter = 4l + 5b = 396 ----(1)

Also, 2I = 3b ----(2)

Put the value of eq. (2) in (1),

=> 4I + 5b = 2×2I+5b = 2×3b+5b = 396

=> (6+5)b = 396

=> b = 396/11

=> b = 36m

Now, finding the length :-

=> l = 3b/2

=> l = 3×36/2

=> I = 108/2

=> I = 54m

Therefore,

Perimeter of the rectangle would be :-

=> 2(l+b)

=> 2(54+36)

=> 2 × 90

=> 180m

Hence, the perimeter of one of the rectangle is 180m.