A rectangle with sides of length (2m – 1) and (2n – 1) units is divided into squares of unit length by drawing parallel lines as shown in the diagram, then the number of rectangles possible with odd side lengths is
(a) (m + n – 1)²
(b) 4m+n–1
(c) m²n²
(d) m(m + 1)n(n + 1)
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I got option c m2n2 I guess that it is correct
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