A rectangulab sheet of paper is 17/3 long and 16/5 wide find its perimeter
Answers
Answer:
Fortherectanglesheet
\begin{gathered}\bold{Length \: (l) = \frac{17}{3} cm} \\\end{gathered}
Length(l)=
3
17
cm
\begin{gathered}\bold{Breadth \: (b) = \frac{16}{5 } cm }\\\end{gathered}
Breadth(b)=
5
16
cm
\bold{\underline{To \: \: find \: \: perimeter}}
Tofindperimeter
\bold{We \: \: know \: \: that}Weknowthat
\begin{gathered}\bold{Perimeter = 2(l + b)} \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =\bold{ 2( \frac{17}{3} + \frac{16}{5} ) \: cm }\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:\bold{ = 2( \frac{85 + 48}{15} ) \: cm }\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{=( 2 \times \frac{133}{15} ) \: cm }\\ \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \bold{= 17.7 \: cm} \: \: \: \bold\red{\boxed{Ans}}\end{gathered}
Perimeter=2(l+b)
=2(
3
17
+
5
16
)cm
=2(
15
85+48
)cm
=(2×
15
133
)cm
=17.7cm
Ans
answer ;
rectangular sheet of paper ( length ) = 17/3 long
rectangular sheet of paper ( wide ) = 16/5 wide
perimeter = Perimeter=2(l+b)
=2( 17/3+16/5 ) cm
=2(85+45)/15 cm
=2× 133/15 cm
=17.7 cm
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