Physics, asked by nyakuarjohn, 10 months ago

A rectangular aluminium solid block of density 2700kg/m3 has dimensional of 40cm ×12cm×6cm.the rests on a horizontal flat surface area calculate minimum and maximum pressure

Answers

Answered by ankita5423
0

Answer:

ANSWER

Given, mass of place of aluminium, m=1kg;

density of aluminium, ρ

s

=2700kg/m

3

;

density of water, ρ

w

=1000kgm

−3

As shown in figure, we have to find tension in the string in each case.

(a) When the aluminium piece is suspended in air

Tension, T=mg [Ref fig. (a)]

or T=1×10=10N

(b) When the aluminium piece is completely immersed in water,

mg=T+F

B

[Ref fig.(b)]

Where, F

B

= buoyant force acting on aluminium

T= tension in the string

∴T=mg−F

B

s

V

s

g−ρ

L

V

L

g

=(ρ

s

V

s

−ρ

L

V

L

)g

=(ρ

s

V

s

−ρ

L

V

s

)g

s

V

s

(1−

ρ

s

ρ

L

)g=(ρ

s

V

s

g)(1−

ρ

s

ρ

L

)

=mg(1−

ρ

s

ρ

L

)

or T

=1×10(1−

2700

1000

)=10(1−

27

10

)

or T

=10(

27

27−10

)=10(

27

17

)

=6.296N.

Hence, the tension in the string before and after the metal is immersed are 10N and 6.296N respectively.

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